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First things first, no coin human or breeze is fair. Anything can happen. There are two choices, heads and tails. We like one, heads. Tails is a no...

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Are you asking the odds of getting heads just one time in fifty flips? That would be very near 100%. The only way that you get no heads is to get f...

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There’s only one way not to get any heads in 50 flips of a coin and that’s to get 50 tails in a row (unlikely, but not impossible). The probability...

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There’s an easy way to tell if you are having an impact or not. Select a particular side and a particular coin. Let’s say a US $0.25 coin, commonly...

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tldr answer: 7.96% How we get there: For one coin flip it is simple: 50%. (1/2) We can remove the other 50% - they have already failed. When we fli...

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You are making a logical mistake that is quite common and has to do with not appreciating how fractions behave in limits. I’ll exaggerate the point...

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The total number of ways to flip 400 coins is [math]{2}^{400}[/math]. So we need to count the number of ways that we’ll get at least 100 heads and...

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Jonathan's answer is elegant and correct. Here is another way to find the answer. There are 2x2x2x2=16 possible combinations of Hs and Ts given 4 c...

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[math]\frac{\binom{100}{50}}{2^{100}}=\frac{100!}{(50!)^2\cdot 2^{100}}\approx 0.07958924[/math] But here’s a fun party trick. If you want to estim...

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There are 8 equally likely possible outcomes: 1. HHH - no 2. HHT - no 3. HTH - no 4. HTT - yes 5. THH - no 6. THT - yes 7. TTH - yes 8. TTT - no So...

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P (h%3E25)=p(h%3E=26)= 1-p(h%3C=26) Assume the situation is approximately normal u= np =50(1/2)=25 , s=√(npq) = √( 50)(.5)(.5) =√12.5 z=(x-u)/s = (...

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Here’s a nice result that’s worth remembering. If you flip a fair coin [math]2n[/math] times, then the probability of getting exactly [math]n[/math...

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Let h and t be the count of heads and the count of tails, respectively. Note that because of symmetry: [math]P(h %3E t) = P(h %3C t)[/math] Now we...

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The sample space of this distribution has 51 elements (0 heads to 50 heads, inclusive) and 25 heads lies exactly in the middle of this distribution...

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In more layman’s terms each coin flip has exactly 0.5 (or 50%) chance either way. With 50 flips its still true, for each individual flip, regardles...

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Flipping a coin and ending with heads is .5 (50%). [one time] Flipping the same coin three times and ending with three heads is .5 x .5 x .5 = .125...

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It’s not going to happen. Every time I flip a coin, it comes up heads. Been that way since 1990 and I’m not going to stop just for a Quora question...

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50% to the ninth power. When the events are independent, you can just multiply all of the probabilities together.

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There are four equally likely outcomes: HH, HT, TH and TT. Of these, two match the criterion given (“one will come up heads and the other tails”)....

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There are 8 equally likely possible outcomes: 1. HHH - no 2. HHT - no 3. HTH - no 4. HTT - yes 5. THH - no 6. THT - yes 7. TTH - yes 8. TTT - no So...

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